A) \[-\sqrt{3}\le x\le \sqrt{3}\]
B) \[-1-\sqrt{3}\le x\le -1+\sqrt{3}\]
C) \[-2\le x\le 2\]
D) \[-2+\sqrt{3}\le x\le -2-\sqrt{3}\]
Correct Answer: B
Solution :
The quantity under root is positive, when \[-1-\sqrt{3}\le x\le -1+\sqrt{3}.\]
You need to login to perform this action.
You will be redirected in
3 sec
