JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    If ?n? is an integer, the domain of the function \[\sqrt{\sin 2x}\] is [MP PET 2003]

    A)                    \[\left[ n\pi -\frac{\pi }{2},\ n\pi  \right]\]

    B)            \[\left[ n\pi ,\ n\pi +\frac{\pi }{2} \right]\]

    C)            \[[(2n-1)\pi ,\ 2n\pi ]\]

    D)            \[[2n\pi ,\ (2n+1)\pi ]\]

    Correct Answer: B

    Solution :

               According to question, as \[\sqrt{\sin 2x}\] can?t be negative.            So the option  is correct                    Domain of function \[\sqrt{\sin 2x}\] is \[[n\pi ,\,n\pi +\pi /2]\].


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