A) \[(-\infty ,\ \infty )\]
B) \[[-2,\ \infty )\]
C) \[(-2,\ 3)\]
D) \[(-\infty ,\ -2)\]
Correct Answer: B
Solution :
\[{{x}^{2}}-6x+7={{(x-3)}^{2}}-2\] Obviously, minimum value is ? 2 and maximum \[\infty \]. Hence range of function is [?2, ¥].
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