JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    The function \[f(x)=\frac{{{\sec }^{-1}}x}{\sqrt{x-[x]}},\] where [.] denotes the greatest integer less than or equal to x is defined for all x belonging to

    A)            R    

    B)                    \[R-\{(-1,\ 1)\cup (n|n\in Z)\}\]

    C)            \[{{R}^{+}}-(0,\ 1)\]

    D)            \[{{R}^{+}}-\{n|n\in N\}\]

    Correct Answer: B

    Solution :

               The function \[{{\sec }^{-1}}x\] is defined for all \[x\in R-(-1,\,\,1)\] and the function \[\frac{1}{\sqrt{x-[x]}}\] is defined for all \[x\in R-Z.\] So the given function is defined for all \[x\in R-\{(-1,\,\,1)\,\,\cup \,\,(n\,\,|\,\,n\in Z)\}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner