A) [1, 4]
B) [?4, 1]
C) [?1, 4]
D) None of these
Correct Answer: A
Solution :
\[f(x)={{\sin }^{-1}}[{{\log }_{2}}(x/2)]\], Domain of \[{{\sin }^{-1}}x\] is\[x\in [-1,\,1]\] Þ \[-1\le {{\log }_{2}}(x/2)\le 1\] Þ \[\frac{1}{2}\le \frac{x}{2}\le 2\] Þ \[1\le x\le 4\] \ \[x\in [1,\,4]\].
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