question_answer

If \[f(x)=\frac{x}{x-1}\], then \[\frac{f(a)}{f(a+1)}=\]                       [MP PET 1996]

A)            \[f(-a)\]

B)            \[f\left( \frac{1}{a} \right)\]

C)            \[f({{a}^{2}})\]

D)            \[f\left( \frac{-a}{a-1} \right)\]