A) One-one only
B) Onto only
C) Both one-one and onto
D) Neither one-one nor onto
Correct Answer: D
Solution :
Let \[f({{x}_{1}})=f({{x}_{2}})\]\[\Rightarrow [{{x}_{1}}]=[{{x}_{2}}]\not{\Rightarrow }{{x}_{1}}={{x}_{2}}\] {For example, if x1=1.4, x2=1.5, then [1.4]=[1.5] =1} \[\therefore \] f is not one-one. Also, f is not onto as its range I (set of integers) is a proper subset of its co-domain R.
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