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JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    Function \[f:R\to R,\ f(x)={{x}^{2}}+x\] is [RPET 1999]

    A)            One-one onto

    B)            One-one into

    C)            Many-one onto

    D)            Many-one into

    Correct Answer: D

    Solution :

               \[\because f(0)=f(-1)=0\] hence \[f(x)\] is many one. But there is no pre-image of \[-1\]. Hence \[f(x)\] is into function. So function is many-one into.


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