A) \[x-2\]
B) \[x+1\]
C) \[x-1\]
D) \[x+2\]
Correct Answer: D
Solution :
Given \[f:(2,\,3)\to (0,\,1)\]and \[f(x)=x-[x]\] \\[f(x)=y=x-2\]Þ\[x=y+2={{f}^{-1}}(y)\Rightarrow {{f}^{-1}}(x)=x+2\].
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