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JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    If \[f(x)={{\sin }^{2}}x\] and the composite function \[g\{f(x)\}=|\sin x|\], then the function \[g(x)\] is equal to            [Orissa JEE 2003]

    A)                    \[\sqrt{x-1}\]

    B)            \[\sqrt{x}\]

    C)                    \[\sqrt{x+1}\]

    D)            \[-\sqrt{x}\]

    Correct Answer: B

    Solution :

               \[(gof)(x)=\,|\sin x|\] and \[f(x)={{\sin }^{2}}x\]                    Þ \[g({{\sin }^{2}}x)=\,|\sin x|\]; \\[g(x)=\sqrt{x}\].


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