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JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    If \[f(x)={{e}^{2x}}\] and \[g(x)=\log \sqrt{x}\]\[(x>0)\], then \[fog(x)\] is equal to

    A)                    \[{{e}^{2x}}\]

    B)            \[\log \sqrt{x}\]

    C)                    \[{{e}^{2x}}\log \sqrt{x}\]

    D)            x

    Correct Answer: D

    Solution :

               \[fog\,(x)=f\{g(x)\}={{e}^{2\log \sqrt{x}}}=x.\]


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