A) \[\frac{x+3}{2}\]
B) \[\frac{x-3}{2}\]
C) \[\frac{1}{2x-3}\]
D) None of these
Correct Answer: A
Solution :
\[y=2x-3\] Þ \[x=\frac{y+3}{2}\] Þ \[{{f}^{-1}}(y)=\frac{y+3}{2}\] Þ \[{{f}^{-1}}(x)=\frac{x+3}{2}\].
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