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JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    The function \[f(x)=\log (x+\sqrt{{{x}^{2}}+1})\], is            [AIEEE 2003; MP PET 2003; UPSEAT 2003]

    A)            An even function               

    B)            An odd function

    C)            A Periodic function            

    D)            Neither an even nor odd function

    Correct Answer: B

    Solution :

               \[f(x)=\log (x+\sqrt{{{x}^{2}}+1})\]                    and \[f(-x)=-\log (x+\sqrt{{{x}^{2}}+1})\]\[=-f(x)\]                    \[f(x)\] is odd function.


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