A) (?1, 1)
B) [0, 1]
C) [?1, 0]
D) (?1, 2)
Correct Answer: B
Solution :
Let \[y={{\sin }^{-1}}\sqrt{x}\,\,\Rightarrow \,\,\sqrt{x}=\sin y\] \[\Rightarrow \,\,x={{\sin }^{2}}y,\,\,\,\,\therefore \,\,0\le x\le 1\]
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