A) \[[0,\ \infty )\]
B) \[[0,\ 3]\]
C) [0, 1]
D) [0, 2]
Correct Answer: C
Solution :
\[{{\sin }^{-1}}\sqrt{x}+{{\cos }^{-1}}\sqrt{x}=\frac{\pi }{2}\]holds x lying in [0,1].
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