A) [5, 9]
B) \[(-\infty ,\ 5]\cup [9,\ \infty )\]
C) (5, 9)
D) None of these
Correct Answer: B
Solution :
Let \[\frac{{{x}^{2}}+34x-71}{{{x}^{2}}+2x-7}=y\] \[\Rightarrow \,\,{{x}^{2}}(1-y)+2\,(17-y)\,x+(7y-71)=0\] For real value of \[x,\,\,{{B}^{2}}-4AC\ge 0\] \[\Rightarrow \,\,{{y}^{2}}-14y+45\ge 0\,\,\Rightarrow y\ge 9,\,\,y\le 5\] .
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