A) 13.81
B) ? 1381.8
C) ? 138.18
D) 1391.6
Correct Answer: B
Solution :
\[\Delta G=-2.303\,RT\,\log \,{K}'\], Here \[R=2\,cal,\,\,T=300K\] \[{K}'=\frac{10\times 15}{3\times 5}=10\]; \[\Delta G=-2.303\times 2\times 300\times {{\log }_{10}}10\] \[=-2.303\times 2\times 300\times 1=-1381.8\,cal\]You need to login to perform this action.
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