• # question_answer A rope, $36\frac{1}{3}m$ long, was cut into three parts measuring $12\frac{2}{5}m$, $13\frac{1}{2}m$ and $5\frac{4}{15}m$ respectively. What was the length of the rope left? A) $5\frac{1}{6}$                 B) $7\frac{2}{5}$C) $9\frac{1}{6}$               D) $11\frac{2}{5}$

$36\frac{1}{3}-\left[ 12\frac{2}{5}+13\frac{1}{2}+5\frac{4}{15} \right]$ $\Rightarrow \frac{109}{3}-\left[ \frac{62}{5}+\frac{27}{2}+\frac{79}{15} \right]$ $\Rightarrow \frac{109}{3}-\left[ \frac{372+405+158}{30} \right]$ $\Rightarrow \frac{109}{3}-\frac{935}{30}=\frac{155}{30}=\frac{31}{6}=5\frac{1}{6}$