| \[\mathbf{1}\frac{\mathbf{3}}{\mathbf{4}}+\mathbf{2}\frac{\mathbf{3}}{\mathbf{8}}=[\,\,?\,\,]+\mathbf{2}\] |
A) 2
B) \[4\frac{1}{8}\]
C) \[2\frac{1}{8}\]
D) \[2\frac{1}{4}\]
Correct Answer: C
Solution :
\[1\frac{3}{4}+2\frac{3}{8}=\frac{7}{4}+\frac{19}{8}=\frac{33}{8}=4\frac{1}{8}=2+2\frac{1}{8}\] \[\therefore \] The missing fraction in the given box is\[2\frac{1}{8}\]
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