• # question_answer Simplify: $4\frac{3}{5}-2\frac{7}{9}-1\frac{2}{15}-\frac{2}{5}$ A)  $\frac{14}{45}$B)  $\frac{13}{45}$C)  $\frac{16}{45}$D)  $\frac{12}{45}$

We have, $4\frac{3}{5}-2\frac{7}{9}-1\frac{2}{15}-\frac{2}{5}$ $=\frac{23}{5}-\frac{25}{9}-\frac{17}{15}-\frac{2}{5}$ Now, LCM of 5, 9 and 15 = 45 $\therefore \frac{23}{5}-\frac{25}{9}-\frac{17}{15}-\frac{2}{5}$ $=\frac{23\times 9}{5\times 9}-\frac{25\times 5}{9\times 5}-\frac{17\times 3}{15\times 3}-\frac{2\times 9}{5\times 9}$ $=\frac{207}{45}-\frac{125}{45}-\frac{51}{45}-\frac{18}{45}=\frac{13}{45}$