• # question_answer If $\frac{3}{4}=\frac{x}{28}=\frac{y}{32}$, then the values of x and y respectively are A)  21, 24B)  21, 28C)  18, 24D)  21, 25

We have, $\frac{3}{4}=\frac{x}{28}\Rightarrow \frac{3\times 7}{4\times 7}=\frac{x}{28}$ $\Rightarrow \frac{21}{28}=\frac{x}{28}$ $\Rightarrow x=21$ Also, $\frac{3}{4}=\frac{y}{32}\Rightarrow \frac{3\times 8}{4\times 8}=\frac{y}{32}\Rightarrow \frac{24}{32}=\frac{y}{32}$ $\therefore y=24$