A) \[(4\times 11)+18\]
B) \[(4\times 8)+11\]
C) \[4\frac{11}{18}\]
D) \[11\frac{4}{18}\]
Correct Answer: C
Solution :
Reciprocals of \[9\] and \[\frac{2}{9}\] are \[\frac{1}{9}\] and\[\frac{9}{2}\] respectively. Their sum\[=\frac{1}{9}+\frac{9}{2}=4\frac{11}{18}\]
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