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6th Class Mathematics Fractions Question Bank Fractions and Decimals

  • question_answer
    Find the value of \[\left( \frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42} \right.\]\[\left. \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}+\frac{1}{132} \right)=?\]

    A) \[\frac{12}{11}\]                                   

    B)  \[\frac{11}{12}\]

    C) \[0\]                             

    D)  \[\frac{13}{12}\]

    Correct Answer: B

    Solution :

    \[\left( \frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}......+\frac{1}{11}-\frac{1}{12} \right)\] \[=1-\frac{1}{12}=\frac{11}{12}\]


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