A) \[\frac{{{d}^{2}}y}{d{{x}^{2}}}-y=0\]
B) \[\frac{{{d}^{2}}y}{d{{x}^{2}}}+y=0\]
C) \[\frac{{{d}^{2}}y}{d{{x}^{2}}}+2y=0\]
D) None of these
Correct Answer: B
Solution :
Given equation \[y=a\cos (x+b)\] Differentiate it w.r.t. x we get \[\frac{dy}{dx}=-a\sin (x+b)\] Again \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=-a\cos (x+b)=-y\] or \[\frac{{{d}^{2}}y}{d{{x}^{2}}}+y=0\].
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