A) \[1.6\times {{10}^{-5}}N\] (attractive)
B) \[1.6\times {{10}^{-5}}N\] (repulsive)
C) \[16\times {{10}^{-5}}N\] (attractive)
D) \[16\times {{10}^{-5}}N\] (repulsive)
Correct Answer: A
Solution :
\[F={{10}^{-7}}\frac{2{{i}_{1}}{{i}_{2}}}{a}={{10}^{-7}}\times \frac{2\times 5\times 8}{0.5}\]\[=1.6\times {{10}^{-5}}\](Attractive)
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