Answer:
(i) Pressure\[=2\times {{10}^{5}}\]pascal = 2 bar (\[\because \]1 bar\[={{10}^{5}}\]Pa) (ii) Pressure \[=2\times {{10}^{5}}\] pascal \[=2\times {{10}^{5}}\times 10\text{ }dynes\text{ }c{{m}^{2}}\] (\[\because \]1 pascal = 10 dyne\[c{{m}^{2}}\]) (iii) Pressure\[=2\times {{10}^{5}}\]pascal \[=2\times {{10}^{5}}\times {{10}^{2}}\]pascal \[=2\times {{10}^{3}}\]millibar (\[\because \]1 millibar\[={{10}^{2}}\] Pa)
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