Answer:
Temperature is constant \[\Rightarrow \] \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[\Rightarrow \]\[{{P}_{2}}=\frac{P\times {{\ell }^{3}}}{8{{\ell }^{3}}}\] \[\Rightarrow \]Boyles law is applicable \[\Rightarrow \]\[P\times {{\ell }^{3}}={{P}_{2}}\times 8{{\ell }^{3}}\] \[\therefore \]\[{{P}_{2}}=\frac{P}{8}\] \[{{1}^{st}}\] Cube \[{{2}^{nd}}\] Cube \[{{\ell }_{2}}=2\ell \] \[{{\ell }_{2}}=2\ell \] \[\Rightarrow \]\[{{V}_{1}}={{\ell }^{3}}\] \[\Rightarrow \]\[{{V}_{2}}={{(2\ell )}^{3}}={{(81)}^{3}}\] \[{{P}_{1}}=P\] \[{{P}_{2}}=?\] Temperature is constant
You need to login to perform this action.
You will be redirected in
3 sec