Answer:
Temperature is constant \[\Rightarrow \] \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] is applicable \[\Rightarrow \] \[{{P}_{1}}\times \frac{4}{3}\pi r_{1}^{3}={{P}_{2}}\times \frac{4}{3}\pi r_{2}^{3}\] \[\left( \because {{V}_{sphere}}=\frac{4}{3}\pi {{r}^{3}} \right)\] \[\Rightarrow \] \[{{P}_{1}}\times r_{1}^{3}={{P}_{2}}\times r_{2}^{3}\] Substituting the values from data in the above equation, we get, \[\Rightarrow \] \[{{P}_{1}}\times {{(2r)}^{3}}={{P}_{2}}\times {{r}^{3}}\] \[\Rightarrow \]\[P\times 8{{r}^{3}}={{P}_{2}}\times {{r}^{3}}\] \[\Rightarrow \] \[{{P}_{2}}=8P\] Case - 1 (First sphere) Case - 1 (First sphere) \[{{r}_{1}}=2r\] \[{{P}_{1}}=P\] \[{{r}_{2}}=r\] \[{{P}_{2}}=?\] Temperature is constant
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