A) 6 m/s
B) 8 m/s
C) 9 m/s
D) 11 m/s
Correct Answer: A
Solution :
\[a=\frac{F}{m}=\frac{1.8\times {{10}^{4}}}{3000}=6\,\,m/{{s}^{2}}\] We know,\[{{v}^{2}}-{{u}^{2}}=2as\] \[\therefore \] \[{{v}^{2}}-0=2\times 6\times 3=36\] \[\Rightarrow \] \[v=6\,\,m/\sec \].You need to login to perform this action.
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