A) Zero
B) 12 Newton
C) 1.2 Newton
D) 0.12 Newton
Correct Answer: D
Solution :
We know, \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[\therefore \] \[200=0\times 10+\frac{1}{2}a{{(10)}^{2}}\] \[\therefore \] \[a=40\,\,cm/{{s}^{2}}\] Now, \[F=m.a\] \[=300\times 40=12000\,\,dynes\] \[\Rightarrow \] \[F=\mathbf{0}\cdot \mathbf{12}\,\,\mathbf{Newton}\]You need to login to perform this action.
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