Answer:
\[F=200\,\,dyne,\,\,m=10g,\,\,t=5s\] \[\therefore \,\,a=\frac{F}{m}=\frac{200}{10}=20cm/{{s}^{2}}\] As a body starts from rest, \[u=0\] From 1st equation of motion \[v=u+at\Rightarrow v=at\] \[\Rightarrow v=20\times 5cm/{{s}^{2}}=100\,\,cm/s\]
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