question_answer

A body of mass 500g is at rest on a frictionless surface. What is the distance travelled by it in 10s when acted upon by a force of\[\text{1}{{0}^{-\text{2}}}\text{ N}\]?

Answer:

\[m=500\,\,\,g=0.5kg,\,\,t=10s\] \[F={{10}^{-2}}\,N=.01N\]and\[u=0\] Now \[a=\frac{F}{m}=\frac{0.01}{0.5}m/{{s}^{2}}=0.02\,m/{{s}^{2}}\] Now\[s=ut+\frac{1}{2}a{{t}^{2}}=\frac{1}{2}[as\,\,u=0]=\frac{1}{2}\times 0.2\times 10\times 10m=1m\]