Answer:
F.D.B of the block of mass(m) \[{{N}_{1}}=\]Normal force by the inclined surface on the block. T = Tension in the rope shown. mg = Gravitational force due to the mass(m) shown \[{{N}_{1}}=\]Normal force by the block of mass (m) on the inclined surface. \[{{N}_{2}}=\]By the horizontal surface on the inclined block of mass(M) (a)
F.B.D of the pulley \[T,{{T}_{1}}\]of the tension in the ropes on either side of the pulley.
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