question_answer

A cricket ball of mass 100 g moving with a speed of 30 m/s is brought to rest by a player. Then find the change in momentum of ball.

Answer:

\[m=100\,\,g=0.1\,\,kg\] \[u=30\,\,m/s\] \[v=0\] Initial momentum \[=mu=0.1\times 30\,\,kg\,m/s=3.0\,\,kg\,\,m/s\] final momentum \[=mv=0.1\times 0=0\] \[\therefore \]change in momentum \[=mv-mu\] \[=-3.0\,kg\,\,m/s\]