Answer:
The net force acting on the block
\[F={{F}_{1}}+{{F}_{2}}\]
\[={{k}_{1}}x+{{k}_{2}}x=-({{k}_{1}}+{{k}_{2}}x)\]
\[\therefore a=\frac{({{k}_{1}}+{{k}_{2}})x}{m}m/{{s}^{2}}\]
opposite to the displacement.
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