question_answer

The velocity - time graph of a particle moving on the ground is shown in figure. If the mass of the particle is 250 g, find the force acting on the particle.

Answer:

\[m=250\,\,g=0.25\,kg\] \[u=10m/s\] \[v=25m/s\] \[Time=t=4\,\sec \] \[F=?\] We know that \[F=ma=n\left( \frac{v-u}{t} \right)\]        …..(1) \[\left( \because a=\frac{v-u}{t} \right)\] \[\therefore \]Substituting the above values in (1), we have, \[F=0.25\left( \frac{25-10}{4} \right)=0.25\left( \frac{15}{4} \right)\] \[\Rightarrow F=\frac{1}{4}\times \frac{15}{4}=\frac{15}{16}N\] Therefore, force acting on the particle is\[\left( \frac{15}{16} \right)N.\]