question_answer

A cricket ball of mass 100 g strikes the hands of a player with a velocity of 20 m/s and is brought to rest in 0.01 s. What is the force applied by the hands of the player?

Answer:

\[m=100\,\,g=0.1\,\,kg\] \[v=20\,\,m/s,\,\,t=0.01\,s\] Now \[a=\frac{V}{t}=\frac{20}{0.01}m/{{s}^{2}}=2000m/{{s}^{2}}\] \[\therefore \,F=m\,\,a=0.1\times 2000\,\,N=200\,\,N\]