A) \[{{x}^{2}}+{{y}^{2}}-hx-ky=0\]
B) \[{{x}^{2}}+{{y}^{2}}+hx+ky=0\]
C) \[3{{x}^{2}}+3{{y}^{2}}+hx-ky=0\]
D) None of these
Correct Answer: A
Solution :
\[y-k=m\text{ }(x-h)\] and \[y-0=-\frac{1}{m}(x-0)\]. Eliminate m and replace (h,k) by \[(x,\,y)\], we get \[{{x}^{2}}+{{y}^{2}}-hx-ky=0\], which is the required locus of the point.
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