A) \[\left( \frac{3}{5},2 \right)\]
B) \[\left( \frac{3}{5},\frac{4}{5} \right)\]
C) \[\left( -\frac{3}{5},-\frac{4}{5} \right)\]
D) \[\left( \frac{30}{17},\frac{19}{17} \right)\]
Correct Answer: B
Solution :
\[d=\frac{5}{\sqrt{{{3}^{2}}+{{4}^{2}}}}=1\] Slope of perpendicular = \[\frac{4}{3}\] Þ \[x=\pm 1.\cos \theta =\pm \frac{3}{5}\]and\[y=\pm 1.\sin \theta =\pm \frac{4}{5}\] Hence \[\left( \frac{3}{5},\frac{4}{5} \right)\] lies on straight line.
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