List-I | List-II | ||
A. | Circular sewer maximum discharge | 1. | Y= 0.938 D |
B. | Maximum velocity in circular sewer | 2. | Y=0.81 D |
C. | Triangular Channel | 3. | \[{{y}_{c}}=\frac{4}{5}\,E,\] \[\frac{v_{c}^{2}}{2g}=\frac{{{y}_{c}}}{4}\] |
D. | Bourdon gauge | 4. | \[{{y}_{c}}=\frac{2}{3}\,E,\] \[\frac{v_{c}^{2}}{2g}=\frac{{{y}_{c}}}{4}\] |
A) A\[\to \]4, B\[\to \]3, C\[\to \]2, D\[\to \]1
B) A\[\to \]3, B\[\to \]4, C\[\to \]1, D\[\to \]2
C) A\[\to \]2, B\[\to \]3, C\[\to \]1, D\[\to \]4
D) A\[\to \]1, B\[\to \]4, C\[\to \]2, D\[\to \]3
Correct Answer: D
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