2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Thermodynamics / रासायनिक उष्मागतिकी

JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank First law of thermodynamics and Hess law

  • question_answer
    At \[{{27}^{o}}C,\] one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm. The values of \[\Delta E\] and q are \[(R=2)\]           [BHU 2001]

    A)                 0, ? 965.84 cal

    B)                 ? 965.84 cal, + 965.84 cal

    C)                 + 865.58 cal, ? 865.58 cal

    D)                 ? 865.58 cal, ? 865.58 cal

    Correct Answer: A

    Solution :

           \[W=2.303\,nRT\,\log \frac{{{P}_{2}}}{{{P}_{1}}}\] \[=2.303\times 1\times 2\times 300\,\log \frac{10}{2}=965.84\]         at constant temperature, \[\Delta E=0.\]                 \[\Delta E=q+w\]; \[q=-w=-965.84\,cal\].


You need to login to perform this action.
You will be redirected in 3 sec spinner