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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank First law of thermodynamics and Hess law

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    The work done by a system is 8 joule, when 40 joule heat is supplied to it. What is the increase in internal energy of system [BHU 2001]

    A)                 25 J        

    B)                 30 J

    C)                 32 J        

    D)                 28 J

    Correct Answer: C

    Solution :

           \[q=40\,J\]         \[w=-8\,J\] (work done by the system)                                 \[\Delta E=q+w=40-8=32\,J\].


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