A) \[2.303\times 298\times 0.082\,\log \,2\]
B) \[298\times {{10}^{7}}\times 8.31\times 2.303\,\log \,2\]
C) \[2.303\times 298\times 0.082\,\log \,0.5\]
D) \[8.31\times {{10}^{7}}\times 298-2.303\,\log \,0.5\]
E) \[2.303\times 298\times 2\,\log \,2\]
Correct Answer: B
Solution :
\[W=2.303\,\,nRT\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[=2.303\,\,\times 1\,\,\times 8.314\,\,\times {{10}^{7}}\,\times 298\,\log \frac{20}{10}\] \[=298\,\,\times {{10}^{7}}\,\times 8.314\,\,\times 2.303\,\,\log \,\,2\].
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