A) Oleic acid
B) linoleic acid
C) Linolenic acid
D) Palmitic acid
Correct Answer: D
Solution :
Oleic acid - \[{{C}_{17}}{{H}_{33}}COOH\], linoleic acid- \[{{C}_{17}}{{H}_{31}}COOH\], linolenic acid - \[{{C}_{17}}{{H}_{29}}COOH\], palmitic acid - \[{{C}_{15}}{{H}_{31}}COOH\]. Saturated monocarboxylic acids form a homologous series which has a general formula \[{{C}_{n}}{{H}_{2n+1}}COOH\] or \[{{C}_{n}}{{H}_{2n}}{{O}_{2}}\]. Only palmitic acid follows this.
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