JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    96500 coulombs of electric current liberates from \[CuS{{O}_{4}}\] solution         [MP PMT 1995]

    A)                 \[63.5\,gm\,Cu\]             

    B)                 \[31.75\,gm\,Cu\]

    C)                 \[96500\,gm\,Cu\]          

    D)                 \[100\,gm\,Cu\]

    Correct Answer: B

    Solution :

                    \[C{{u}^{++}}+2{{e}^{-}}\to Cu\];  \[{{E}_{Cu}}=\frac{63.55}{2}=31.75\,\,gm\,\,Cu\].


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