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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    The number of electrons passing per second through a cross-section of copper wire carrying \[{{10}^{-6}}\] amperes of current per second is found to be       [EAMCET 1985]

    A)                 \[1.6\times {{10}^{-19}}\]            

    B)                 \[6\times {{10}^{-35}}\]

    C)                 \[6\times {{10}^{-16}}\]               

    D)                 \[6\times {{10}^{12}}\]

    Correct Answer: D

    Solution :

               Charge (Coulombs) pass per second \[={{10}^{-6}}\]            number of electrons passed per second                                 \[=\frac{{{10}^{-6}}}{1.602\times {{10}^{-19}}}=6.24\times {{10}^{12}}\].


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