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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    On passing 0.5 faraday of electricity through \[NaCl\], the amount of \[Cl\] deposited on cathode is [BHU 1997; RPET 1999]

    A)                 35.5 gm               

    B)                 17.75 gm

    C)                 71 gm   

    D)                 142 gm

    Correct Answer: B

    Solution :

               Equivalent of Cl deposited            = No. of Faraday passed = 0.5                                 Wt. of \[Cl=0.5\times Eq.\,wt.\]\[=0.5\times 35.5=17.75\,\,gm\].


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