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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    To deposit 0.6354 gm of copper by electrolysis of aqueous cupric  sulphate solution, the amount of electricity required (in coulombs) is                                [MP PMT 1989]

    A)                 9650      

    B)                 4825

    C)                 3860      

    D)                 1930

    Correct Answer: D

    Solution :

               \[C{{u}^{++}}+2{{e}^{-}}\to Cu\]            \[{{E}_{Cu}}=\frac{63.54}{2}=31.77\]                 Amount of electricity required to deposit .6354 gm of Cu \[=\frac{96500\times 0.6354}{31.77}=1930\,Coulombs\].


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