A) 10.8 mg
B) 5.4 mg
C) 16.2 mg
D) 21.2 mg
Correct Answer: A
Solution :
\[{{W}_{Ag}}=\frac{{{E}_{Ag}}\times Q}{96500}=\frac{108\times 9.65}{96500}\] \[=1.08\times {{10}^{-2}}gm=10.8\,mg\]
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