A) \[\left( x+3 \right)\left( 2x+1 \right)\]
B) \[\left( x-3 \right)\left( 2x-1 \right)\]
C) \[\left( x+2 \right)(x-1)\]
D) \[\left( x+3 \right)(2x-1)\]
Correct Answer: D
Solution :
(d): \[2{{x}^{2}}-5x+3\] Using same process as in Q9, Roots \[=-\,3\] and\[\frac{1}{2}\]' \[\therefore (x+3)\left( x-\frac{1}{2} \right)=0\] or\[\left( x+3 \right)\left( 2x-1 \right)=0.\]
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